Flower garden has shape of right triangle, 5' of a perenial border forms hypotenuse of triangle.?
x^2 + (x+1)^2 = 25
2x^2 + 2x + 1 = 25
x^2 + x - 12 = 0
(x + 4)(x - 3) = 0
.. . .
thus the legs are 3' and 4'
.. . .. .
Reply:it is a well known axiom that one 'standard' form of a right triangle is when the sides are 3, 4 and 5 - which is exactly what you describe!
Reply:Let other sides be x and (x + 1)
52 = x2 + (x + 1)2
x2 + x2 + 2x + 1 = 25
2x2 + 2x - 24 = 0
x2 + x - 12 = 0
(x + 4)(x - 3) = 0
x = 3 is accepted
Sides are 3 ft and 4 ft
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